(x^2+2x+40)=(x^2-x+190)

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Solution for (x^2+2x+40)=(x^2-x+190) equation: 



(x^2+2x+40)=(x^2-x+190)

We move all terms to the left:

(x^2+2x+40)-((x^2-x+190))=0

We get rid of parentheses

x^2+2x-((x^2-x+190))+40=0



We calculate terms in parentheses: -((x^2-x+190)), so:

(x^2-x+190)

We get rid of parentheses

x^2-x+190

We add all the numbers together, and all the variables

x^2-1x+190

Back to the equation:

-(x^2-1x+190)



We get rid of parentheses

x^2-x^2+2x+1x-190+40=0

We add all the numbers together, and all the variables

3x-150=0

We move all terms containing x to the left, all other terms to the right

3x=150

x=150/3

x=50

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